Instructor: Dennis DeTurck
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ANNOUNCEMENTS:
I will have "regular" office hours on Mondays from 6-7:30 pm, somewhere (TBA -- probably at my place in the Quad, since that's a pretty central location). "Regular" means that during those times, I'm there for my Math 104 students, and I'm not allowed to tell you I'm busy (unless it's with another student). There will be other times that I will announce either in class or by email (and they'll always be posted on this website). You are welcome to stop by at other times (during the day usually in Cohen Hall or in the evening or on weekends in Riepe), but at those times I reserve the right to ask you to come back later if I'm involved with other stuff.
Homework will be assigned before each Thursday, and will be due at Thursday's lecture the following week. You will almost always need to use the computer to do some of your homework.
Homework will contain instructions for reading. Make sure you do the reading before the class for which it is assigned. I will assume you have done so.
Make use of my office hours, Math Center, Maple Center, Electronic newsgroups (upenn.math.math104), Sunday Night Reviews (schedule to be announced soon) etc..
Grading notes: At the end of the semester, everyone who has not withdrawn from the class will get a grade. Incompletes will not be given to avoid F's.
LATE WORK (homework, Maple, etc..) will NEVER be accepted.
Ways to get help:
Class notes:
Homework and class notes:
Bonus problems and solutions:
Bonus problem #2: Consider a square with side length L. Let R be the region inside the square consisiting of all points that are closer to the center of the square than to any side of the square. What is the area of R ?
This is an interesting problem -- the hard part is to draw a good picture of the region and get equations for its (curved) sides. (Can you do it with Maple?)
Bonus problem #3: Prove that (explain why) log3(11) is an irrational number.
A speedy solution, by Joshua Jackson:
Suppose log3(11) = n
where n = a/b, and a and b are both
(nonzero) integers (this would define
n as a
rational number.) Then
log3(11) = a/b
b log3(11) = a
log3(11b) = a
3a = 11b
So, for log3(11) to be a rational number, there must exist nonzero integers a and an integer b for which the above statement is true. Because the prime factorization of any number is different from that of any other number, and 3a and 11b are examples of numbers that have been simplified to their prime factors, there cannot be integers a and b for which 3a = 11b, and so log3(11) cannot be a rational number.
Therefore, log3(11) is an irrational number.